solitaire
and topology
2012–09–28
Do they play nicely?
Do they talk to each other?
And if they do, what do they say to each other?
basics
Warning: this is rubbish. Rubbish written by an idiot who thinks that he knows more than he does. I might have something here but please do not treat what follows as in any way true.
Can we create a topological space that represents a solitaire board? The answer is yes, in fact we can create many. What we need is a useful one, or a useful several perhaps. I’m going to create[?] one that has some interesting properties and some interesting oddities.
You can’t play solitaire seriously for long before you notice the classes. Let’s have a look at them [for the English board, which I’m going to restrict this analysis to for now]. In a pretence at mathematical rigour, let X be the union of all the filled holes of a solitaire board, and let A, B, C and D be proper subsets of X. Let’s have a look at these A, B, C and D’s, shall we?.
0 | 1 | 2 | 3 | 4 | 5 | 6 | |
---|---|---|---|---|---|---|---|
0 | - | - | - | - | |||
1 | - | - | • | - | - | ||
2 | |||||||
3 | • | • | • | ||||
2 | |||||||
5 | - | - | • | - | - | ||
6 | - | - | - | - |
0 | 1 | 2 | 3 | 4 | 5 | 6 | |
---|---|---|---|---|---|---|---|
0 | - | - | • | • | - | - | |
1 | - | - | - | - | |||
2 | • | • | • | • | |||
3 | |||||||
4 | • | • | • | • | |||
5 | - | - | - | - | |||
6 | - | - | • | • | - | - |
0 | 1 | 2 | 3 | 4 | 5 | 6 | |
---|---|---|---|---|---|---|---|
0 | - | - | • | - | - | ||
1 | - | - | - | - | |||
2 | • | • | • | ||||
3 | |||||||
4 | • | • | • | ||||
5 | - | - | - | - | |||
6 | - | - | • | - | - |
0 | 1 | 2 | 3 | 4 | 5 | 6 | |
---|---|---|---|---|---|---|---|
0 | - | - | - | - | |||
1 | - | - | • | • | - | - | |
2 | |||||||
3 | • | • | • | • | |||
4 | |||||||
5 | - | - | • | • | - | - | |
6 | - | - | - | - |
The basic point is that no peg can move from one class to another, and it has to interact with another class to be able to move. [And A, B, C and D are disjoint and their union is X.] If we are going to discuss solitaire topologically it would seem to make sense that these are open sets. These alone aren’t a topological space, we need to include all the unions. I won’t write this down, it’s a horrible thing to look at and doesn’t get us any further forward. Let’s just call this topology ΤS
Let’s notice that X is disconnected.
the idea
For now is that if we can find an iterated function that ends with a connected courser-topology…? A single point?
However before we tackle that we have something tricky to think about—we want this to be a metricizable topology, what is a distance on a solitaire board? We’ll tackle that next time.